type_test_with_undefined_name
The name '{0}' isn't defined, so it can't be used in an 'is' expression.
Description
#The analyzer produces this diagnostic when the name following the is
in a type test expression isn't defined.
Example
#The following code produces this diagnostic because the name Srting
isn't defined:
dart
void f(Object o) {
if (o is Srting) {
// ...
}
}
Common fixes
#Replace the name with the name of a type:
dart
void f(Object o) {
if (o is String) {
// ...
}
}
Unless stated otherwise, the documentation on this site reflects Dart 3.7.3. Page last updated on 2025-05-08. View source or report an issue.