integer_literal_imprecise_as_double

The integer literal is being used as a double, but can't be represented as a 64-bit double without overflow or loss of precision: '{0}'.

The analyzer produces this diagnostic when an integer literal is being implicitly converted to a double, but can't be represented as a 64-bit double without overflow or loss of precision. Integer literals are implicitly converted to a double if the context requires the type double.

The following code produces this diagnostic because the integer value 9223372036854775807 can't be represented exactly as a double:

double x = 9223372036854775807;

If you need to use the exact value, then use the class BigInt to represent the value:

var x = BigInt.parse('9223372036854775807');

If you need to use a double, then change the value to one that can be represented exactly:

double x = 9223372036854775808;